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Next, Es0:∞,a0:∞ [∇θ log πθ(at | st)bt(s0:t, a0:t−1)] = Es ,a 0:t 0:t−1 = Es ,a 0:t 0:t−1 Es ,a [∇θ log πθ(at | st)bt(s0:t, a0:t−1)] t+1:∞ t:∞ Es ,a [∇θ log πθ(at | st)] bt(s0:t, a0:t−1) t+1:∞ t:∞ = Es0:t,a0:t−1 [0 · bt(s0:t, a0:t−1)] = 0. 4.9 proofs 63PDF Image | OPTIMIZING EXPECTATIONS: FROM DEEP REINFORCEMENT LEARNING TO STOCHASTIC COMPUTATION GRAPHS
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